You can check if a year is a leap year in Python using the following logic:

def is_leap_year(year): if (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0): return True else: return False # Test the function year = int(input("Enter a year: ")) if is_leap_year(year): print(f"{year} is a leap year.") else: print(f"{year} is not a leap year.")

This code defines a function `is_leap_year`

that takes a year as input and returns `True`

if it’s a leap year and `False`

if it’s not. The logic checks whether the year is divisible by 4 and not divisible by 100, or if it’s divisible by 400. If either of these conditions is met, the year is considered a leap year.

## What is the formula for leap year in Python?

The formula to determine if a year is a leap year can be expressed in Python as follows:

def is_leap_year(year): return (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0)

This concise formula uses the same logic as mentioned earlier: a leap year is either divisible by 4 and not divisible by 100, or it is divisible by 400. The `is_leap_year`

function will return `True`

if the year is a leap year and `False`

otherwise.

## Is 1992 a leap year, use Python?

Yes, 1992 is a leap year in Python, as well as in the Gregorian calendar. You can use the `is_leap_year`

function mentioned earlier to confirm this:

def is_leap_year(year): return (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0) year = 1992 if is_leap_year(year): print(f"{year} is a leap year.") else: print(f"{year} is not a leap year.")

When you run this code, it will print: “1992 is a leap year.” This is because 1992 satisfies the conditions for a leap year (divisible by 4 and not divisible by 100).

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